Showing posts with label Volume. Show all posts
Showing posts with label Volume. Show all posts
Saturday, 25 May 2019
Thursday, 23 May 2019
Aptitude Hack#93(27-5-19)
Question:
How many spherical bullets can be made out of a lead cylinder 28cm high and with radius 6 cm, each bullet being 1.5 cm in diameter?
A ) 1795
B ) 1892
C ) 1772
D ) 1792
Answer : D) 1792
Explaination :
Volume of cylinder = (∏ x 6 x 6 x 28) cm3
Volume of each bullet = ( 9∏/16) cm3.
Number of bullets =
The volume of cylinder /Volume of bullet
= [(36 x 28)∏ x 16] /9∏ = 1792.
How many spherical bullets can be made out of a lead cylinder 28cm high and with radius 6 cm, each bullet being 1.5 cm in diameter?
A ) 1795
B ) 1892
C ) 1772
D ) 1792
Answer : D) 1792
Explaination :
Volume of cylinder = (∏ x 6 x 6 x 28) cm3
Volume of each bullet = ( 9∏/16) cm3.
Number of bullets =
The volume of cylinder /Volume of bullet
= [(36 x 28)∏ x 16] /9∏ = 1792.
Wednesday, 15 May 2019
Aptitude Hack#89(23-5-19)
Question:
A Cone, a hemisphere and a cylinder stand on equal bases and have the same height. Find the ratio of their volumes.
A ) 2:4:6
B ) 1:5:8
C ) 1:2:3
D ) 1:4:6
Answer: C) 1:2:3
Explanation:
Let R be the radius of each
Height of the hemisphere = Its radius = R.
Height of each = R.
Ratio of volumes
= (1/3)∏ R2 x R : (2/3)∏R3 : ∏ R2 x R
= 1:2:3
A Cone, a hemisphere and a cylinder stand on equal bases and have the same height. Find the ratio of their volumes.
A ) 2:4:6
B ) 1:5:8
C ) 1:2:3
D ) 1:4:6
Answer: C) 1:2:3
Explanation:
Let R be the radius of each
Height of the hemisphere = Its radius = R.
Height of each = R.
Ratio of volumes
= (1/3)∏ R2 x R : (2/3)∏R3 : ∏ R2 x R
= 1:2:3
Tuesday, 14 May 2019
Monday, 13 May 2019
Aptitude Hack#80(14-5-19)
Question:
The dimensions of an open box are 50 cm, 40 cm, and 23 cm. Its thickness is 2 cm. If 1 cubic cm of metal used in the box weighs 0.5 gms, find the weight of the box.
A ) 7.04 kg
B ) 6.04 kg
C ) 8.04 kg
D ) 9.04 kg
Answer: C) 8.04 kg
Explanation :
The volume of the metal used in the box
= external volume – internal volume
= [(50 * 40 * 23) – (44 * 34 * 20)]cm3
= 16080 cm3
Weight of the metal =((16080*0.5)/1000)kg
= 8.04 kg.
The dimensions of an open box are 50 cm, 40 cm, and 23 cm. Its thickness is 2 cm. If 1 cubic cm of metal used in the box weighs 0.5 gms, find the weight of the box.
A ) 7.04 kg
B ) 6.04 kg
C ) 8.04 kg
D ) 9.04 kg
Answer: C) 8.04 kg
Explanation :
The volume of the metal used in the box
= external volume – internal volume
= [(50 * 40 * 23) – (44 * 34 * 20)]cm3
= 16080 cm3
Weight of the metal =((16080*0.5)/1000)kg
= 8.04 kg.
Saturday, 27 April 2019
Sunday, 21 April 2019
Aptitude Hack#57(21-4-19)
Question:
In a shower, 5 cm of rain falls. The volume of water that falls on 1.5 hectares of the ground is:
A) 75 ㎥
B) 750 ㎥
C) 7500 ㎥
D) 75000 ㎥
Answer: B) 750 ㎥
Explanation:
1 hectare = 10,000 ㎡
So, Area = (1.5 x 10000) ㎡ = 15000 ㎡.
Depth = 5/100 m = 1/20 m.
Volume = (Area x Depth)
=15000 X1/20 ㎥ = 750 ㎥.
In a shower, 5 cm of rain falls. The volume of water that falls on 1.5 hectares of the ground is:
A) 75 ㎥
B) 750 ㎥
C) 7500 ㎥
D) 75000 ㎥
Answer: B) 750 ㎥
Explanation:
1 hectare = 10,000 ㎡
So, Area = (1.5 x 10000) ㎡ = 15000 ㎡.
Depth = 5/100 m = 1/20 m.
Volume = (Area x Depth)
=15000 X1/20 ㎥ = 750 ㎥.