Question:
The present ages of three persons in proportions 4:7:9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).
A) 8, 20, 28
B) 16, 28, 36
C) 20, 35, 45
D) None of these
Answer B) 16, 28, 36
Explanation:
Let their present ages be 4x, 7x and 9x years respectively.
Then,
(4x- 8) + (7x - 8) + (9x - 8) = 56
20x = 80
Their present ages are
4x = 16 years,
7x = 28 years and
9x = 36 years respectively.
7x = 28 years and
9x = 36 years respectively.
GG Sharma.
ReplyDelete