Question:
What is the sum of two consecutive odd numbers, the difference of whose squares is 56?
A) 30
B) 28
C) 34
D) 32
Answer: B) 28
Explanation:
Let the no. be x and (x +2).
Then (x +2)^2 – x^2 = 56
4x + 4 = 56
x + 1 = 14
x = 13
Sum of numbers = x + (x +2) = 28
Alternate solution:-
Let two numbers be x and y.
x^2 + y^2 =56
(x-y)(x+y)=56
//x-y would be 2 as the numbers odd and they are consecutive.
//we have asked sum of numbers i.e x+y
(x+y)=56/2=28.
What is the sum of two consecutive odd numbers, the difference of whose squares is 56?
A) 30
B) 28
C) 34
D) 32
Answer: B) 28
Explanation:
Let the no. be x and (x +2).
Then (x +2)^2 – x^2 = 56
4x + 4 = 56
x + 1 = 14
x = 13
Sum of numbers = x + (x +2) = 28
Alternate solution:-
Let two numbers be x and y.
x^2 + y^2 =56
(x-y)(x+y)=56
//x-y would be 2 as the numbers odd and they are consecutive.
//we have asked sum of numbers i.e x+y
(x+y)=56/2=28.
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