Question:
A bag contains 50 Ps, 25 Ps and 10 Ps coins in the ratio 5: 9: 4, amounting to Rs. 206. Find the number of coins of each type.
A ) 160, 360, 200
B ) 360, 160 , 200
C ) 200, 360, 160
D ) 200, 160, 360
Answer:C) 200,360,160
Explanation:
Let the number of 50 Ps, 25 Ps, and 10 Ps coins are 5x, 9x and 4x respectively.
(5x/2)+( 9x/ 4)+(4x/10) ==> 206
==> 50x + 45x + 8x = 4120
==> 103x = 4120
==> x=40.
Number of 50 Ps. coins = (5 x 40) = 200
Number of 25 Ps. coins = (9 x 40) = 360
Number of 10 Ps. coins = (4 x 40) = 160
A bag contains 50 Ps, 25 Ps and 10 Ps coins in the ratio 5: 9: 4, amounting to Rs. 206. Find the number of coins of each type.
A ) 160, 360, 200
B ) 360, 160 , 200
C ) 200, 360, 160
D ) 200, 160, 360
Answer:C) 200,360,160
Explanation:
Let the number of 50 Ps, 25 Ps, and 10 Ps coins are 5x, 9x and 4x respectively.
(5x/2)+( 9x/ 4)+(4x/10) ==> 206
==> 50x + 45x + 8x = 4120
==> 103x = 4120
==> x=40.
Number of 50 Ps. coins = (5 x 40) = 200
Number of 25 Ps. coins = (9 x 40) = 360
Number of 10 Ps. coins = (4 x 40) = 160
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