Question:
A dog takes 4 leaps for every 5 leaps of a hare but 3 leaps of a dog are equal to 4 leaps of the hare. Compare their speeds.
A ) 16:15
B ) 17:15
C ) 18:25
D ) 19:35
Answer: A) 16:15
Explanation :
Let the distance covered in 1 leap of the dog be x and that covered in 1 leap of the hare by y.
Then, 3x = 4y
=> x = 4/3y
=> 4x = 16/3 y.
The ratio of speeds of dog and hare =
The ratio of distances covered by them at the same time
= 4x: 5y = 16/3 y: 5y =16/3: 5 = 16:15
A dog takes 4 leaps for every 5 leaps of a hare but 3 leaps of a dog are equal to 4 leaps of the hare. Compare their speeds.
A ) 16:15
B ) 17:15
C ) 18:25
D ) 19:35
Answer: A) 16:15
Explanation :
Let the distance covered in 1 leap of the dog be x and that covered in 1 leap of the hare by y.
Then, 3x = 4y
=> x = 4/3y
=> 4x = 16/3 y.
The ratio of speeds of dog and hare =
The ratio of distances covered by them at the same time
= 4x: 5y = 16/3 y: 5y =16/3: 5 = 16:15
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