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Wednesday 5 June 2019

Aptitude Hack#102(5-6-19)

Question:

Ram and Hari started from A and B, towards B and A at 6.00 am and 7.00 am respectively. They meet each other at 9.00 am and continued towards their respective destinations. Ram reaching B turns back and catches up with Hari before Hari reaches A at 11.00 am. At what time will Hari reach A.

 (a) 7.00 pm
 (b) 4.00 pm
 (c) 5.00 pm
 (d) 6.00 pm

Answer: (d) 6.00pm 

Explanation:
Let the speed of Ram is “x” and that of Hari is “y”. 
After 3hrs of Ram started from A (6.00 am) and after 2hrs Hari started from B (7.00 am), both meet at 9.00 am. So during their meet distance traveled by Ram is 3x and by Hari is 2y.
Again they meet at 11.00 am, 2hrs from 9.00 am. During this 2 hr distance traveled by Ram is 2x.



 And the distance traveled by Hari is 2y. As Ram has reached B and again turns back towards A and then they both meet at 11.00am, the distance covered in terms of y is 2y(from 1st meeting to B) +2y(from B to 1st meeting point)+2y(from 1st meeting point to 2nd meeting point)= 6y.
 Thus 2x=6y => x=3y 
Thus the total distance between A and B is 3x+2y=11y 
Hari has already covered 4y distance. For covering the remaining 7y distance, he needs 7 hrs. So the time is 11.00 am +7hrs= 6pm.

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