Aptitude Hack#83(17-5-19)

Question:

The ages of two persons differ by 16 years. If 6 years ago, the elder one is 3 times as old as the younger one, find their present ages.

   A )   15 years and 31 years
   B )   14 years and 30 years   
   C )   13 years and 29 years
   D )   12 years and 28 years

Answer: B)14 years and 30 years   

Explanation:

 Let the age of the younger person be x years.

Then, age of the elder person = (x + 16) years.

=> 3 (x – 6) = (x + 16 – 6)
=> 3x -18 = x + 10
=> 2x = 28
=> x = 14.

Hence, their present ages are 14 years and 30 years.